## Monday, March 22, 2010

### Irodov Problem 3.19

The electric flux through the circle is given by,

Where E is the electric field and dS is the area vector through which E passes. From problem 3.14 we already know that E is given by,

Consider an infinitesimally thin ring section of radius r and width dr. The area vector of this infinitesimally thin ring section is given by,

Hence the flux is given by,

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